79 Grundlagen der Elektrotechnik 2.18 Temperatur Angewandte Mathematik Körper • Pyramide AM = hs1 . l 1 + hs2 . l 2 AO = AM + l1 . l 2 V = l1 . l2 . h 3 h = 3 . V l1 . l 2 hs1 = h 2 + l2 2 4 √ hs2 = h 2 + l1 2 4 √ ANGEWANDTE MATHEMATIK • Kegel V = d2 . π . h 4 3 hs = d2 + h2 4 √ AM = hs . d . π 2 hs2 = (l1 – l2) 2 + h2 4 hs1 = (l3 – l4) 2 + h2 4 • Pyramidenstumpf V = h . (A1 + A2 + A1 . A 2) 3 √ AM = (l1 + l2) . h s1 + (l3 + l4) . h s2 AO = AM + l1 . l 3 + l2 . l 4 V = d 3 . π 6 • Kugel AO = d 2 . π d = AO oder d = 6 . V π √ π √ V = h2 . π . D – h 2 3 ( ) AO = D . π . h + d 2 . π 4 • Kugelabschnitt AM = D . π . h hs = (D – d)2 + h2 4 AM = hs . π . (D + d) 2 • Kegelstumpf V = h . π . (D2 + d2 + D .d) 12 √ √ 3 √ MUSTER
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